Maxim/minimum extrema derivatives
one model of worldwide oil production is the function given by the following formula where p(t) is the # of barrels in billions produced in a year, t years after 1933. according to this model, in what yaer did worldwide oil production achieve an absolute maximum? what was that maximum?

p(t)=0.218t^4-0.167t^3 0.00156t^2 0.002t 0.22 0 (theyre greater than or equal too)

so every time the phrase 'minimum' or 'maximum' show up in a problem with an equation, it means we need to do the math operation of taking the derivative. make senes?can you find the derivative of the equation given?

4.1billion barrels in 2005

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!

96 39 cause 135 -96=39 im smart (i used a calculater)