Professor Cramer determines a final grade based on attendance, two papers, three major tests, and a final exam. Each of these activities has a total of 100 possible points. However, the activities carry different weights. Attendance is worth 3%, each paper is worth 9%, each test is worth 17%, and the final is worth 28%. (a) What is the average for a student with 81 on attendance, 90 on the first paper, 92 on the second paper, 86 on test 1, 71 on test 2, 93 on test 3, and 62 on the final exam

78.67

Step-by-step explanation:

The computation of the average for a student is shown below:

= Different Weights × different activities

= (3% × 81) + (9% × 90) + (9% × 92) + (17% × 86) + (17% × 71) + (17% × 93) + (28% × 62)

= 2.43 + 8.1 + 8.28 + 14.62 + 12.07 + 15.81 + 17.36

= 78.67

Hence, the average of the student is 78.67

We simply applied the above formula

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation:

figure c

step-by-step explanation:

hope this .