Let bold r 1 comma ... Comma bold r subscript pbe vectors in set of real numbers r superscript n, and let q be an m times n matrix. Write the matrix left bracket upper q bold r 1 ...Q bold r subscript p right bracket as a product of two matrices (neither of which is an identity matrix).

Answer and Step-by-step explanation:

Let bold r 1 comma ... Comma bold r subscript p be vectors in the set of real numbers r superscript n:

r1,… ,rp be vector in Rn

And let Q be an m times n matrix = Q= m x n

write the matrix left bracket upper q bold r 1 ...Q bold r subscript p right bracket as a product of two matrices = [Qr1, …, QrP], which is a product of two matrices.

To write the product of two matrices.

Use the definition of AB in reverse order:

[Qr1, …, QrP] = Q [r1, …, rp]

                       = QR

the answer would be d

straight away you can eliminate a and c because not all books contain a scientific skill because some may be fiction. c is also wrong because it saids that the only way children can learn is through books which is incorrect.

b is also wrong because reading can be a scientific skill but not always, therefore it is wrong which leaves you with d, the correct answer since it said that it can children learn.

hope this ! : 3

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)