What is the 96th term of -16,-28,-40 hi

Tn = a + (n - 1) d

where a = first term

n = number of the member of the sequence

d = common difference

a = -16

n = 96

d = second term - first term or

third term - second term

= -28 - (-16) = -28 + 16 = -12 or

= -40 - (-28) = -40 + 28 = -12

d = -12

Tn = a + (n - 1) d

= -16 + (96 - 1) -12

= -16 + (95) -12

= -16 + (-1140)

= -16 - 1140 = -1156

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

what's that