John took a 5 1/2 mile walk to his friend's house. He left at 11 a. M. And arrived at his friend's house at 12:45 p. M. Therefore it took him 1 3/4 hours to get to his friends house. If the return trip took 2 1/4 hours, what is the average speed on the return trip?

The average speed on the return trip is 2.44 miles/h.                  

Step-by-step explanation:

To find the average speed we need to use the following equation:

Where:

d: is the distance

t: is the time

Since the question is to find the average speed on the return trip, we will take the data of the time and speed of only the return trip.

Therefore, the average speed on the return trip is 2.44 miles/h.

I hope it helps you!

answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

step-by-step explanation: mark as brainlest reallly need it thx

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130