Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee for installation. Which inequality can be used to find out when the monthly cost for Cable company A is less than Cable company B? 39x+30<45x+18 45x+18>39x+30 45x+18<39x+30 39x+18<45x+30

Question

Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee for installation. Which inequality can be used to find out when the monthly cost for Cable company A is less than Cable company B?

a)39x+30<45x+18

b) 45x+18>39x+30

c) 45x+18<39x+30

d)39x+18<45x+30

c) 45x+18<39x+30

Step-by-step explanation:

Step 1

We have to find the Algebraic expressions for the cable companies

Cable company A charges $45 a month for cable plus a $18 installation fee.

Let the number of months be represented as x

Hence, this is represented as:

$45 × x + $18

= 45x + 18

Cable B charges $39 a month for cable plus a $30 fee for installation.

Let the number of months be represented as x

Hence, this is represented as:

$39 × x + $30

= 39x + 30

The inequality that can be used to find out when the monthly cost for Cable company A is less than Cable company B?

= Cable company A < Cable company B

= 45x + 18 < 39x + 30

Therefore option c is correct

step-by-step explanation:

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