What is an equation of the line that passes through the points (0,-7) and (-6,-2)

y=(-5/6)x-7

Step-by-step explanation:

Let the line graph y=ax+b,

b=-7 as (0,-7) is y-intercept

To get a (slope), slope a = (y2-y1)/(x2-x1) = (-2-(-7))/(-6-0)=-5/6

Thus, y=(-5/6)x-7

let f (x ) is a function and c be a positive real number,   the graph of the function g (x ) = f (cx ) is represented as follows.

when, c > 1,   the function compresses it in the x - direction.

when, 0 < c < 1, the function stretches it.

the function is g ( x ) = (9x )2.

the heighest power of x in g ( x ) = (9x )2 is 2, so the parent function is square function.

the equation of parent function is f ( x ) = x 2 .

the function is g ( x ) = (9x )2 and the parent function is f ( x ) = x 2 .

so, the functions f and g have the following relationship.

g ( x ) = f ( 9x ).

compare the function g ( x ) = f ( 9x ) with g (x ) = f (cx ).

c = 9 ( > 1 ).

so, the function g (x ) = (9x )2 compresses it in the x - direction.

step-by-step explanation: