If the sum of 4 consecutive numbers is 126, what is the first number?
The first number is

Work Shown:

Consecutive numbers follow right after another (eg: 7,8,9,10,...)

x = first number

x+1 = second number

x+2 = third number

x+3 = fourth number

Add up the expressions and set this equal to 126

(x) + (x+1) + (x+2) + (x+3) = 126

x+x+1+x+2+x+3 = 126

(x+x+x+x) + (1+2+3) = 126

4x+6 = 126

4x = 126-6

4x = 120

x = 120/4

x = 30 = first number

x+1 = 30+1 = 31 = second number

x+2 = 30+2 = 32 = third number

x+3 = 30+3 = 33 = fourth number

Check:

30+31+32+33 = 126

Answer is confirmed.

it's both, now can you answer my most recent question?