Graph the line with slope
−3/4

passing through the point
, (3,3)

Y = mx + b
slope(m) = -3/4
(3,3)x = 3 and y = 3
now we sub and find b, the y int
3 = -3/4(3) + b
3 = -9/4 + b
3 + 9/4 = b
12/4 + 9/4 = b
21/4 = bor 5.25 for graphing purposes

so ur equation is : y = -3/4x + 21/4

ur y int = (0,21/4) or (0,5.25)

ur x int can be found by subbing in 0 for y and solving for x
y = -3/4x + 21/4
0 = -3/4x + 21/4
3/4x = 21/4
x = 21/4 * 4/3
x = 84/12 = 7so ur x int is (7,0)

so plot ur points (7,0) and (0,5.25)now start at (0,5.25) and since the slope is -3/4, come down 3 spaces and go to the right 4 spaces, then down 3, and to the right 4 and u will eventually cross the x axis at (7,0)

What do you mean by that?