Aparticle is moving along a projectile path where the initial height is 160 feet with an initial speed of 144 feet per second. what is the maximum height of the particle?

Assuming Earth's gravity, the formula for the flight of the particle is: s(t) = -16t^2 + vt + s = -16t^2 + 144t + 160. This has a maximum when t = -b/(2a) = -144/[2(-16)] = -144/(-32) = 9/2. Therefore, the maximum height is s(9/2) = -16(9/2)^2 + 144(9/2) + 160 = 484 feet. I got this answer from Yahoo.com

X=3 and y=4 is the answer