One factor of the polynomial x^3 − 7x^2 + 13x − 3 is (x − 3). What is the other factor of the polynomial? (Note: Use long or synthetic division.) A. (x^2 + 4x − 1)
B. (x^2 − 4x + 1)
C. (x − 4)
D. (x + 4)

B. (x^2 − 4x + 1)

I hope this helps.

Option (B)

Step-by-step explanation:

Given polynomial in the question is,

x³ - 7x² + 13x - 3

One factor of the polynomial is (x - 3).

That means x = 3 is a zero factor of the polynomial.

For the other factor,

By using synthetic division,

3 |   1         -7           13           -3

                  3           -12          3  

     1          -4            1            0

= (x² - 4x + 1)(x - 3)

Therefore, the other factor of the polynomial is (x² - 4x + 1).

Option (B) will be the answer.

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.