Leslie has two cups containing different-colored paper clips. The first cup contains 7 pink paper clips and 3 blue paper clips. The second cup contains 3 black paper clips, 1 red paper clip, and 6 orange paper clips. What is the probability that Leslie will randomly select a blue paper clip from the first cup and then randomly select an orange paper clip from the second cup? *

9/50 = 0.18

Step-by-step explanation:

The first cup has 10 paper clips, 3 of which are blue.

The second cup has 10 paper clips, 6 of which are orange.

So the probability is:

P = (3/10) (6/10)

P = 9/50

P = 0.18

a is 8.b is 10.c is 10.5. d is -.5

step-by-step explanation:

just minus the smallest number from the biggest.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.