ruger has a dartboard with an area of 1600 cm^2. The dartborad has a circular bullseye centered at (0 cm, 0 cm). The point ( square root 3cm, square root 7cm) is on the circumference of the bullseye.

A percentage is given by dividing a given value by a total and multiplying the result by 100

The percentage of the dartboard occupied by the bullseye is approximately 1.963 %

Reason:

The given parameters are;

The area of the dartboard, A = 1,600 cm²

The location of the center of the bullseye = (0 cm, 0 cm)

The coordinates of a point on the circumference = (√3 cm, √7 cm)

Question: Possible question with regards to the given parameter; The percentage of the dartboard covered by the bullseye

Solution;

The radius of the bullseye, r =

The area of the bullseye, = π· r² = π × = 10·π

∴ The area of the bullseye, = 10·π cm²

The percentage area is given as follows;

Therefore;

The percentage of the dartboard occupied by the bullseye ≈ 1.963 %

Learn more about percentage area here:

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percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

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b

step-by-step explanation: