A concave mirror produces three times enlarged virtual image of an object at 10 cm in front of it calculate the radius of curvature of the mirror

Given that, magnification is 3 times enlarged and virtual image. So m=+3(because +represents virtual image and 3 tells us that the height of image is 3 times that of object. Since, m=-(v/u) 3 = -(v/-10cm) v=30cm By mirror formula, 1/f = 1/v +1/u = 1/30 + 1/-10 =-2/30 f=-15cm Since R=2f=2x(-15cm)=-30cm Ans: The Radius of curvature measures -30cm

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find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

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y

=

−

2

find the upper bound of the range.

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y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: