Choose the equation of the line passing through the point (-1, 7) and perpendicular to y = -x - 5. y = -4x - 11 y = -4x - 3 y = 4x 11 y = 4x 3

For perpendicular lines, the product of their slopes is -1, i.e. m1m2 = -1 => m2 = -1/m1
Line y = -x - 5 has a slope of -1, therefore, the required line will have a slope of -1/-1 = 1.
Required equation is
y - 7 = (x - (-1))
y - 7 = x + 1
y = x + 1 + 7
y = x + 8

What class is this? i have no idea and i'm not going to give you the wrong answer. do you have a graph that goes with all the questions