As part of a social experiment, Joey sent an email to 2 friends. The email asks the person reading it to forward it to 3 people. The table shows the distribution of the email, assuming that everyone who recelves the email forwards it to 3 new people. Number of iterations Number of People Recelving the Email.

I can not see the table, so i will answer this in a general way.

Ok, let's see a rough image of what is happening.

First, Joey sends the email to 2 friends.

So first, 2 people have the email

Then each friend sends the email to 3 new people.

So now the number of people that has the email is:

2 + 2*3 = 2 + 6.

Now, the 6 new people that received the email send it to other 3 new people each, so now the number of people that got the email is:

2 + 6 + 6*3

and so on.

We already can see the pattern here, we can write this as:

∑aₙ

Where aₙ = 3*aₙ₋₁

and a₀ = 2.

So with that information, we can find the number of iterations, n, for a given number of people that received the email A.

A = ∑aₙ = (a₀ + a₁ + a₂ + ) = (2 + 2*3 + 2*3*3 + ...)

im pretty sure its

(8,15)

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.