How can I use a scale to help me find the actual perimeter of an object if I already know the perimeter of the scale drawing?

Lets say you have a scale of 2 actual feet is equal to 1 graph inch. And lets say you have a perimeter of 24 inches. You know that for every inch I have graphed, it's an actual 2 feet. So if you multiply those 24 inches by 2, then you will get 48. And you need to change the units to match the description, so I will need to change inches to feet. This will get me 48 feet of perimeter in real life.

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

the two may have that, even a breakdown is probably offered