Jasmine purchased 3 bags of hot cheetos and 2 packs of sour patch kids from the vending machine and spent 5.25. Michael also loaded up on snacks for the week and purchased 7 bags of hot Cheetos and 3 packs of sour patch kids for 9.75. Which is the cost of a bag of hot Cheetos and a pack of sour patch kids?

cost of a bag of hot Cheetos = 0.75 and cost of a pack of sour patch kids = 1.5

Step-by-step explanation:

Let the cost of a bag of hot cheetos be c

Let the cost of a pack of sour patch kids be k

Thus, for Jasmine, the equation will be;

3c + 2k = 5.25 - - - - (eq1)

For Michael, the equation will be;

7c + 3k = 9.75 - - - - - (eq2)

We will use method of elimination to solve this.

Multiply (eq 1) by 3 and (eq 2) by 2 to give;

9c + 6k = 15.75 - - (eq4)

14c + 6k = 19.5 - - -(eq5)

Subtract (eq4) from (eq 5) to get;

5c = 19.5 - 15.75

5c = 3.75

c = 3.75/5

c = 0.75

Put 0.75 for c in (eq 4) to get;

9(0.75) + 6k = 15.75

6.75 + 6k = 15.75

6k = 15.75 - 6.75

6k = 9

k = 9/6

k = 1.5

Thus; cost of a bag of hot Cheetos = 0.75 and cost of a pack of sour patch kids = 1.5

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation:

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)