A city hold an election for mayor every two years and the election for treasure ever six-year it held elections for both mayor and Treasurer this year how many years will it be before the election for mayor and treasure both happened in the same year

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.

they disappear if your absent from to long. i found out that the hard way.

step-by-step explanation:

brainliest lol i just need one more brainliest.

answer: 270

step-by-step explanation:

you have to times 200 by 1.35 to get your answer