A dot-com company ships products from three different warehouses (A, B, and C). Based on customer complaints, it appears that 3% of the shipments coming from A are somehow faulty, as are 5% of the shipments coming from B, and 2% coming from C. suppose a customer is mailed an order and calls in a complaint the next day. What is the probability the item came from Warehouse C

The probability of getting defective product from warehouse C is 0.3448

Step-by-step explanation:

Missing question "Assume that Ware houses A, B and C ship 30%, 20% and 50% of the dot-com's sales respectively.

P(A) = Probability of product that comes from warehouse A

P(B) = Probability of product that comes from warehouse B

P(C) = Probability of product that comes from warehouse C

P(A) =  30% = 0.30, P(B) =  20% = 0.20, P(C) =  50% = 0.50

Let D denotes the number of defective products

P(D|A) = 3% = 0.03

P(D|B) = 5% = 0.05

P(D|C) = 2% = 0.02

The probability of getting defective product from warehouse C is as below using the Bayes Rule

P(C|D) = P(D|C) P(C) / P(D|A)P(A) + P(D|B)P(B) + P(D|C)P(C)

P(C|D) = 0.02 * 0.50 / (0.03*0.30) + (0.05*0.20) + (0.02*0.50)

P(C|D) = 0.01 / 0.009 + 0.01 + 0.01

P(C|D) = 0.01 / 0.029

P(C|D) = 0.3448

Therefore the probability of getting defective product from warehouse C is  0.3448.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15