If we have a group of 5 men and 4 women and we select two at random, without replacement, then find the probability that one of each gender is selected

Step-by-step explanation:

If we have a group of 5 men and 4 women, the total number of people we have is 5+4 = 9 people

Total outcome = 9people

For us to select one of each gender without replacement and selecting two at random means we can select a male before a female or a female before a male.

Let W =Women and M = Male

The Probability of selecting two at random without repalcement is given as;

= Pr(W)Pr(M) + Pr(M)Pr(W)

= (4/9*5/8)+(5/9*4/8) (Note that the total number reduces by 1 during the second pick since we aren't replacing the person we picked first)

= 20/72 + 20/72

= 40/72

= 20/36

= 5/9

Hence the the probability that one of each gender is selected is 5/9

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all

what are you trying find out?

step-by-step explanation: