Given line segment RB and on it is point C, if RB = 45 and CB = 3x - 12 and RC = 2x + 9, what is the value of x?

x = 9.6

Step-by-step explanation:

Since point C is on line segment RB.

Therefore,

RC + CB = RB

2x + 9 + 3x - 12 = 45

5x - 3 = 45

5x = 45 + 3

5x = 48

x = 48/5

x = 9.6

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.