Point F is on line segment \overline{EG} EG . Given FG=8,FG=8, EF=2x+4,EF=2x+4, and EG=4x-10,EG=4x−10, determine the numerical length of \overline{EF}. EF .

26 units

Step-by-step explanation:

If point F is on the line segment EG, then EF+FG = EG

Given

FG=8,

EF=2x+4

EG=4x−10

Substitute the given values into the formula;

2x+4+8 = 4x−10

2x+12 = 4x-10

collect like terms

2x-4x = -10-12

-2x = -22

x = 22/2

x =11

Since EF = 2x+4

EF = 2(11)+4

EF = 22+4

EF = 26

Hence the numerical length of EF is 26 units

9 x 8 divided by (5-3)=36