Which quadratic equation is equivalent to (x2 – 1)2 – 11(x2 – 1) + 24 = 0? u2 – 11u + 24 = 0 where u = (x2 – 1) (u2)2 – 11(u2) + 24 where u = (x2 – 1) u2 + 1 – 11u + 24 = 0 where u = (x2 – 1) (u2 – 1)2 – 11(u2 – 1) + 24 where u = (x2 – 1)

your answer would be 10x - 1

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.