-3a+6b=a+4b I need to solve this please.

a*2=b

Or

a=0, b=0

Step-by-step explanation:

if a=0 and b=0, then 0=0, it'd be correct, but I'm sure that's not the answer they intend you to pick. You should still put that as one of the answers, however.

-3a+6b=a+4b

+3a     +3a

6b=4a+4b

-6b     -6b

0=4a-2b

/2 /2  /2

0=2a-b

so, we now know that b is twice the amount that a is, and actually, that's the solution for the entire thing.

So, the answer is a*2=b, because the equation works for any set of numbers, as long as it follows this rule.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

oof cheaters cheat because they’re lazy that’s why i cheat xd

: )

step-by-step explanation: