Write the equation of a line that passes through (2,-1) and is PARALLEL to y = -3x + 4 The equation is

y = -3x + 5

Step-by-step explanation:

Since the line is parallel, we know that the slope of our line must be equal to the one given.

The given equation is:

y = -3x + 4

and thus, it has a slope of -3

As such, our unknown equation...

y = kx + m

...must have the same k-value, or the same slope, of -3.

y = -3x + m

Now we just need to find m. We know that our line passes through the point (2, -1), or in other words, when x = 2, y = -1

We can put these values for x and y into our equation.

y = -3x + m

-1 = -3 * 2 + m

-1 = -6 + m

Adding 6 to both sides:

5 = m

m = 5

Putting m = 5 into our equation:

y = -3x + m

y = -3x + 5

..we find that our equation is

y = -3x + 5

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0