What is the equation of the line that passes through (−5, 0) and (4, 3)? A. y=1/3x+5/3
B. y=-1/3x-5
C. y=3x+15
D. y=-3x-15

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m =

with (x₁, y₁ ) = (- 5, 0) and (x₂, y₂ ) = (4, 3)

m = = = , thus

y = x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (4, 3) , then

3 = + c ⇒ c = 3 - =

y = x + → A

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?