Which of the following are solutions to the equation below? Check all that apply. 4x2 + 4x + 1 = 9

4x^2 + 4x + 1=9

4x^2 + 4x - 8=0

Dividing both sides by 4

x^2 + x -2=0

It can be written as

x^2 + 2x - x - 2=0

x(x+2) -1(x+2)=0

taking (x+2) as common on LHS

Then, (x+2)(x-1)=0

Now first equate x+2=0  ie x=-2

then                 x-1=0 ie x=1

Therefore, x has two values(roots)

that is -2,1

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i

(-5,-28)

i graphed to on desmos.