Let f (x) = sqrt x and g (x) = 3x+2. find the range of (f. g) (x)

[0, infinity)

Step-by-step explanation:

Focus on f(x) = sqrt(x) first.  The domain of this function is [0, infinity), and the range is [0, infinity).

The product (f*g)(x) is sqrt(x)*(3x + 2).

This leads to the conclusion that the range of  (f.g) (x) is  identical to the range of sqrt(x), which is [0, infinity).

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl