find three consecutive odd intergers such that the sum of the smalest number and middle number is 27 less than 3 times the largest number.

x+(x+2)+(x+4)

x+(x+2) = 3(x+4)-27

2x+2 = 3x+12-27

2x+2 = 3x-15

2 = 1x-15

1x = 2+15

1x = 17

x = 17

The 3 consecutive no's are: x=17, x+2= 17+2 = 19, x+3= 17+4 = 21

imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation: