scores on the act college entrance exam follow a bell-shaped distribution with mean 18 and standard deviation 6. Wayne's standardized score on the ACT was -0.5. what was Wayne's actual ACT score?

His actual score is 15

Step-by-step explanation:

Here, we are interested in calculating Wayne’s actual score on the ACT

when we say the scores have being standardized, it means the score was reported in terms of the z-score and not the initial raw scores.

Now, mathematically, for the scores to have a negative z-score, it means it is actually below the mean.

The formula for the z-score or standard score is given below;

z-score = (x - mean)/SD

where in this case, x = ? which is the score we are looking for , z-score = -0.5 , mean score = 18 and standard deviation of the scores = 6

So, substituting these values into the z-score equation, we have;

-0.5 = (x-18)/6

x-18 = 6(-0.5)

x -18 = -3

x = -3 + 18

x = 15

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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step-by-step explanation: