What order will result in a final output of 131,065 when the first input is 64

1. h(x) = 2ˣ-7 :  

2ˣ - 7 = 131,065  

2^x = 131,072  

x = 17  

2. k(x) = -(x/2) - 1 = 17  

x/2 = -18  

x = -36  

3. g(x) = -(x-2)² = -36  

x - 2 = 6  

x = 8  

4. f(x) = √x = 8  

x = 64  

h(k(g(f(64 = 131,065

Step-by-step explanation:

I hope this help

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: