Find two consecutive whole numbers that square root of 31 lies between.
answer this please.

The consecutive whole numbers that the square root of 31 lies between will be 5 and 6.

Consecutive numbers simply refers to the numbers that follow each other in a particular set.

The square root of 31 is 5.57

Therefore, it can be noted that 5.57 will be between 5 and 6.

Therefore, the numbers are 5 and 6.

Read related link on:

link

Given :

An irrational number , .

To Find :

Two consecutive whole numbers that square root of 31 lies between.

Solution :

We know , square root of 36 is 6.

Also, square root of 25 is 5.

Now, we can see that lies between 5 and 6. Also, both 5 and 6 are consecutive.

Therefore, between 5 and 6 is the solution.

Hence, this is the required solution.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

step-by-step explanation:

f(x)=2x^2 -1 

translation is a function transformation that transform the function in a way of translating. by translating the function its graph is moved  up an down. moving the function f(x) 2 units to the left will be the new function g(x) with the equation: g(x)=f(x+2)=2(x+2)^2 -1