6h−(9−3h)=6−3(h+2)

a. h=3/2

b. h=3/4

c. h=7/2

d. h=17/6

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: