A lioness hunting antelope runs a distance of 60 m in 15 s. Then she stops to survey the herd for 20 s. Next, she trots for 25 s over 60 m around the edge of the herd. Finally, the lioness races after the antelope, traveling 120 m in 20 s. What is the average speed of the lioness?

The average speed is 3m/s.

Step-by-step explanation:

We can define the average speed as the quotient between the total distance traveled in a given period of time, and that period of time,

Here we have that:

d = distance

t = time.

"A lioness hunting antelope runs a distance of 60 m in 15 s"

1) d = 60m, t = 15s

"Then she stops to survey the herd for 20 s"

We add 0 meters to the distance, and 20 seconds to the time.

2) d = 60m + 0m, t = 15s + 20s = 35s

"she trots for 25 s over 60 m around the edge of the herd."

we add 60m to the distance, and 25s to the time

3) d = 60m + 60m = 120m, t = 35s + 25s = 60s.

"Finally, the lioness races after the antelope, traveling 120 m in 20 s"

we add 120m to the distance and 20s to the time.

4) d = 120m + 120m = 240m, t = 60s + 20s = 80s.

Then the average speed of the lioness in that period of time is:

S = 240m/80s = 3m/s

its d but looking at that hurts my eyes frfr

step-by-step explanation:

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17