The period, T, of a pendulum of length l is given by T = f(l) = 2π√l/g, where g is a constant. Find f^-1.

When effective length (L) is constant, the time period (T) of oscillation of a simple pendulum is inversely proportional to the square root of the acceleration due to gravity (g) at a place of observation. So, T∝√1g when L is constant.

Step-by-step explanation:

the correct is answer is a 9-sided polygon!

here is your mark brainliest