Mathematics, 25.09.2020 22:01 cubist7472
Find the smallest solution to negative 5 e superscript negative 4 x plus 2 baseline plus 3 equals one half log left parenthesis x squared plus 1 right parenthesis and describe the steps you used. Round your answer to three decimals.
Answers: 3
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Find the smallest solution to negative 5 e superscript negative 4 x plus 2 baseline plus 3 equals on...
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