Point B is on line segment \overline{AC} AC . Given AB=6AB=6 and BC=12,BC=12, determine the length \overline{AC}. AC .

18

Step-by-step explanation:

AB+BC=

AB+BC=

\,\,AC

AC

Segment addition postulate

6+12=

6+12=

\,\,AC

AC

Plug in known values

18=

18=

\,\,AC

AC = 18

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."