Solve: 6(t-3) = 2(9 - 2t)
T=

6(t-3)=2(9-2t)=

We move all terms to the left:

6(t-3)-(2(9-2t))=0

We add all the numbers together, and all the variables

6(t-3)-(2(-2t+9))=0

We multiply parentheses

6t-(2(-2t+9))-18=0

We calculate terms in parentheses: -(2(-2t+9)), so:

2(-2t+9)

We multiply parentheses

-4t+18

Back to the equation:

-(-4t+18)

We get rid of parentheses

6t+4t-18-18=0

We add all the numbers together, and all the variables

10t-36=0

We move all terms containing t to the left, all other terms to the right

10t=36

t=36/10

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.