(look at the image) can i get help with these 2 questions?

18. ∠AED= ∠BEC (vert. opp. ∠s)

2x -11= 105

2x= 105 +11

2x= 116

x= 116 ÷2

x= 58

∠AEB= 180° -105° (adj. ∠s on a str. line)

∠AEB= 75°

∠BEC= 105° (vert. opp. ∠s)

∠CED= ∠AEB (vert. opp. ∠s)

∠CED= 75°

∠AED= 105° (given)

19. ∠AEB +∠BEC= 180° (adj. ∠s on a str. line)

6x +19 +x= 180

7x +19= 180 (simplify)

7x= 180 -19 (-19 on both sides)

7x= 161 (simplify)

x= 161 ÷7

x= 23

∠AEB= 6(23) +19

∠AEB= 157°

∠BEC= 23°

∠CED= ∠AEB (vert. opp. ∠s)

∠CED= 157°

∠AED= ∠BEC (vert. opp. ∠s)

∠AED= 23°

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1