Given f(x) = -x – 1, solve for x when f(x) = -10.
Plz help not sure how to do it

-X=9

Step-by-step explanation:

f(x)=-x-1

Plug in -10

-10=-x-1

add 1 to -10

-9=-x

which means -x=-9

to check, plug everything in

-10=-9-1

-10=-10

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

what's the question?

step-by-step explanation:

there is no question.