Use the information given to find a convenient class width. Then list the class boundaries that can be used to create a relative frequency histogram. (Round your class width up to the nearest multiple of 5. Use the minimum value as the smallest class boundary. Enter your class boundaries as a comma separated list.)

hello some information is missing below is the missing information

8 classes for n = 75 measurements; minimum value = 20; maximum value = 175

answer : width = 20

               class boundary : 20,40,60,80,100,120,140,160,180

Step-by-step explanation:

Using the information given the convenient class width

= (maximum value - minimum value) / number of class

= ( 175 - 20 ) / 8

= 155 / 8 = 19.375 to the nearest multiple of 5 =  20

Using the minimum value as the smallest class boundary

the class boundary will be :

20,40,60,80,100,120,140,160,180

since the maximum value 175

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72