3 Consider the set X = { 1 , 2 , 3 , 4 , 5 } and suppose you have two holes. Also suppose that you have 10 pigeons: the 2 -element subsets of X . Can you put these 10 pigeons into the two holes in a way that there is no 3 -element subset S = { a , b , c } ⊂ X for which all pigeons from S go in the same hole? Then answer the same question if X = { 1 , 2 , 3 , 4 , 5 , 6 } with 15 = C ( 6 , 2 ) pigeons.

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step-by-step explanation:

sadsdda

step-by-step explanation:

$655.61 which is option c

step-by-step explanation:

price of house =   $146,000

initial rate = 3.5%

mortgaged paid in this = 3.5 % of $146,000

                                        =

                                        =$5110

the total years would be = 7

total mortgaged paid = 7 * $5110

                                      =$35770

remaining money = $146000-35770

                                =$110230

new mortgaged payment = 5 % of 110230

                                            =  

                                            =$655.61