The perimeter of a rectangle is 700 yards. What are the dimensions of the rectangle if the length is 50 yards more than the width?

width = 150 yards

length = 200 yards

Step-by-step explanation:

Using the information given to us, we can make the following two equations:

2L + 2W = 700

L = W + 50

where L is the length in yards and W is the width in yards. This could treat these two equations as a system of linear equations. There are multiple ways to solve a system of linear equations, but I am going to solve this by substitution. Before doing that, I am first going to simplify the first equation, as it will make solving the system easier.

2L + 2W = 700

Divide both sides by 2.

L + W = 350

Since L = W + 50, we can substitute W + 50 for L in the equation L + W = 700.

(W + 50) + W = 350

2W + 50 = 350

2W = 300

W = 150

Now that we found what W is, we can solve for L by plugging 150 into either one of the equations. I am going to plug it into the equation L = W + 50.

L = 150 + 50

L = 200

Now we found what L is. So now we know that the width is 150 yards and the length is 200 yards.

I hope you find my answer and explanation helpful. Happy studying. :)

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.