Given the following function, find f(-2), f(0), and f(4). f(x)=x2-4
f(-2) =
f(0) =
f(4)=

f(-2) = 0

f(0) = -4

f(4) = 12

Step-by-step explanation:

Given the function f(x) = x^2 - 4, we must plug in the values substituting x for each of the answers.

f(-2) = (-2)^2 - 4

-2 times itself is a positive 4, therefore:

f(-2) = 4 - 4

f(-2) = 0

We do the same for each answer.

f(0) = (0)^2 - 4

f(0) = -4

f(4) = (4)^2 - 4

f(4) = 16 - 4

f(4) = 12

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

what i would say the best answer is a. 40.5