What is the domain of the square root function graphed below? On a coordinate plane, a curve opens down to the right in quadrant 1. The curve starts at (3, 1) and goes through (4, 2) and (7, 3).
x greater-than 1
x greater-than-or-equal-to 10
x greater-than 3
x greater-than-or-equal-to 3

it is c, trust i got your back lol

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

positive

step-by-step explanation:

the quadrant is facing upwards