An article described an experiment in which observations on various characteristics were made using minichambers of three different types: (1) cooler (PVC frames covered with shade cloth), (2) control (PVC frames only), and (3) warmer (PVC frames covered with plastic). One of the article's authors kindly supplied the accompanying data on the difference between air and soil temperatures (°C). Cooler Control Warmer 1.59 1.92 2.57 1.43 2.00 2.60 1.88 2.19 1.93 1.26 1.12 1.58 1.91 1.78 2.30 1.86 1.84 0.84 1.90 2.45 2.65 1.57 2.03 0.12 1.79 1.52 2.74 1.72 0.58 2.53 2.41 1.90 2.13 2.34 2.86 0.84 2.31 1.34 1.91 1.76 (a) Compare measures of center for the three different samples. Cooler = Control = Warmer = (b) Calculate the standard deviations for the three different samples. (Round your answers to three decimal places.) Cooler s = 0.393 Control s =

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316

the answer is 99.

the population of other specie of birds will decline or other specie of birds will find some alternate source of food to survive.

explanation:

according to the competitive exclusion principle, which is also known as gause's law, two specie living in the same niche and feeding on the same resource cannot co-exist stably.

as we have well studied the theory of natural selection which states that only those organisms survive which have better tendency to compete for food and adapt to the environmental conditions.

coming towards the question, what wi ll happen when one species outcompetes the other for the small fish , the other specie will not get enough food and will start to die or decline in population. eventually either other specie needs to find another alternative food source for itself or migrate at some other location where there is less competition otherwise it will just not exist anymore at that niche.

hope it !