find the base of isolation triangle whose area is 60 CM square and length of one of its equal side is 13 cm

base = 10 cm

Step-by-step explanation:

The height from the vertex is a perpendicular bisector of the isosceles Δ

This line divides the triangle into 2 right triangles with hypotenuse 13

Thus each right triangle is a 5- 12- 13 with legs 5 and 12

The height is 12 cm and the base 5 cm

Then the base of the isosceles Δ = 2 × 5 cm = 10 cm

Note Area = 0.5 × 10 × 12 = 60 cm²

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.