Which domain window settings would be appropriate if you wanted to graph the function below in degrees for exactly 3 periods?
y = 4sin(3x)
O Xmin=-90 Xmax = 270
O Xmin=-- Xmax = x
O Xmin = 0 Xmax = 120
Xmin = 0 Xmax = 3,1

The domain window setting is the minimum and maximum x-values of a function.

The appropriate domain window settings are: and

We have:

A sine function is represented as:

Where:

period

By comparing and

We have the value of B to be:

For a sine function, the value of 1 period (T) is:

Convert to degrees

The difference between the domain window settings is then calculated as follows:

So, we have:

This means that the difference between the window settings must be

The option that satisfies this condition is:

(a) and

This is so, because:

Substitute and

Open brackets

Hence, the appropriate domain window settings are:

and

Read more about domains at:

link

The domain window setting that would be appropriate to graph the function is;

= -90°, = 270°

Step-by-step explanation:

The given equation is y = 4·sin(3·x)

We note that one period of the sine function = 2·π = 360°

Therefore, if we wanted to graph the above function for exactly three periods, then we should have;

The domain of the function will be from 0 to 3 × 360

Minimum value of 3·x = 0,

Maximum value of 3·x= 3 × 360°

Therefore;

Minimum value of x = 0°/3 = 0° and maximum value of x = 3 × 360°/3 = 360°

Which gives the extent of the domain as 360°

The appropriate domain window setting to graph the function therefore, = -90°, = 270° as the extent is 270 - (-90) = 360°

answer is : muchas/tipicas

have a nice day!

~recklesschicken