Question 3 (2 points) Using the statement below, determine the hypothesis and conclusion,

If two integers are even, then their sum is even

Column A

Column B

1.

Hypothesis

a. If two integers are even

2.

Conclusion

b. then their sum is even

c. two integers are even

d. their sum is even

Hypothesis

a. If two integers are even

Conclusion

b. then their sum is even

Step-by-step explanation:

We divide the statement into two parts . The first part is true only when the second is also true. The only way we can reject the hypothesis is that the conclusion is false.

In the statement "If two integers are even, then their sum is even" the part "If two integers are even" would be considered true or false on the basis of "then their sum is even" validity. So if the "then their sum is even" (conclusion )  Part is proved then the "If two integers are even" ( hypothesis) is also true.

Hence the hypothesis is

a. If two integers are even

and

Conclusion is

b. then their sum is even

the range of a function is the range of y-values for which it is defined, or exists. given that we are only looking at the y-values, we can already discount the first two answers as they deal with the domain of the function (range of x-values).

now, what we need to do is find the smallest and highest y-values for which the function is defined. if you'd like, you could take a ruler and start at the very bottom of the graph, find the lowest point, then move the ruler higher and higher until you reach the highest point. doing so either in your head or with an actual ruler, we can see that the lowest y-value is -5 and the highest y-value is -1.

the question now remains as to whether they are included in the range (fourth answer) or excluded (third answer). the key here is to recognise whether they are marked with an open or a closed circle. since both (-2, -5) and (2, -1) are marked with a closed circle, they are points that exist on the graph and are thus included in the range (note that if they were marked with an open circle like (4, -2) then that would signify that there is a break in the graph at that point).

thus, the fourth answer, (y | -5 ≤ y ≤ -1), is correct.

also note that usually it is good practice to scan your eye inbetween the highest and lowest point for any breaks in the graph - we do have one here at (4, -2), however -2 is still included in the range because there is another point that is included in the graph with the same y-value, ie. point (1, -2).

i hope that but if you require any further explanation don't hesitate to comment below.

idek

step-by-step explanation: